C Program to Check Whether Two Numbers are Amicable or Not

Program :-

#include <sidio.h>
main(){
    int num1,num2,i,j,sum1=0,sum2=0;
    printf("enter two numbers :\n");
    scanf("%d%d",&num1,&num2);
    for(i = 1; i <= num1 / 2; i++)
   {
        if(num1 % i ==0)
            sum1 = sum1 + i ;
    }
    for(j = 1; i <= num2 / 2; i++)
   {
        if(num2 % i ==0)
            sum2 = sum2 + i ;
    }
    if(num1 == sum2 && num2 == sum1)
        print("\n numbers are amicable");
    else
        print("\n numbers are not amicable");
}

Output :-

enter two numbers :
220
284
numbers are amicable

Algorithm to Check Whether Two Numbers are Amicable or Not

Step 1 : Start

Step 2 : Read Num1, Num2

Step 3 :  i = 1

Step 4 : if  i <=  Num1 / 2 then go to Step 5 
             else go to Step 8
Step 5 : if  Num1 % i = 0 then go to Step 6
             else go to Step 7
Step 6 : Sum1 = Sum1 + i
Step 7 : i = i + 1 , then  go to Step 4
Step 8 : i = 1
Step 9 : if  i <=  Num2 / 2 then go to Step 10 

             else go to Step 13
Step 10 : if  Num2 % i = 0 then go to Step 11
             else go to Step 12
Step 11 : Sum2 = Sum2 + i

Step 12 : i = i + 1 , then  go to Step 9
Step 13 : if Sum1 = Num2 and Sum2 = Num1 then go to Step 14
               else go to Step 15 
Step 14 : print "Numbers are Amicable" ,go to Step 16
Step 15 : print "Numbers are not amicable" ,go to Step 16
Step 16 : Stop